3.3.49 \(\int x^6 (a^2+2 a b x^2+b^2 x^4)^2 \, dx\)

Optimal. Leaf size=56 \[ \frac {a^4 x^7}{7}+\frac {4}{9} a^3 b x^9+\frac {6}{11} a^2 b^2 x^{11}+\frac {4}{13} a b^3 x^{13}+\frac {b^4 x^{15}}{15} \]

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Rubi [A]  time = 0.03, antiderivative size = 56, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {28, 270} \begin {gather*} \frac {6}{11} a^2 b^2 x^{11}+\frac {4}{9} a^3 b x^9+\frac {a^4 x^7}{7}+\frac {4}{13} a b^3 x^{13}+\frac {b^4 x^{15}}{15} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^6*(a^2 + 2*a*b*x^2 + b^2*x^4)^2,x]

[Out]

(a^4*x^7)/7 + (4*a^3*b*x^9)/9 + (6*a^2*b^2*x^11)/11 + (4*a*b^3*x^13)/13 + (b^4*x^15)/15

Rule 28

Int[(u_.)*((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Dist[1/c^p, Int[u*(b/2 + c*x^n)^(2*
p), x], x] /; FreeQ[{a, b, c, n}, x] && EqQ[n2, 2*n] && EqQ[b^2 - 4*a*c, 0] && IntegerQ[p]

Rule 270

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*(a + b*x^n)^p,
x], x] /; FreeQ[{a, b, c, m, n}, x] && IGtQ[p, 0]

Rubi steps

\begin {align*} \int x^6 \left (a^2+2 a b x^2+b^2 x^4\right )^2 \, dx &=\frac {\int x^6 \left (a b+b^2 x^2\right )^4 \, dx}{b^4}\\ &=\frac {\int \left (a^4 b^4 x^6+4 a^3 b^5 x^8+6 a^2 b^6 x^{10}+4 a b^7 x^{12}+b^8 x^{14}\right ) \, dx}{b^4}\\ &=\frac {a^4 x^7}{7}+\frac {4}{9} a^3 b x^9+\frac {6}{11} a^2 b^2 x^{11}+\frac {4}{13} a b^3 x^{13}+\frac {b^4 x^{15}}{15}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 56, normalized size = 1.00 \begin {gather*} \frac {a^4 x^7}{7}+\frac {4}{9} a^3 b x^9+\frac {6}{11} a^2 b^2 x^{11}+\frac {4}{13} a b^3 x^{13}+\frac {b^4 x^{15}}{15} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^6*(a^2 + 2*a*b*x^2 + b^2*x^4)^2,x]

[Out]

(a^4*x^7)/7 + (4*a^3*b*x^9)/9 + (6*a^2*b^2*x^11)/11 + (4*a*b^3*x^13)/13 + (b^4*x^15)/15

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^6 \left (a^2+2 a b x^2+b^2 x^4\right )^2 \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[x^6*(a^2 + 2*a*b*x^2 + b^2*x^4)^2,x]

[Out]

IntegrateAlgebraic[x^6*(a^2 + 2*a*b*x^2 + b^2*x^4)^2, x]

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fricas [A]  time = 0.68, size = 46, normalized size = 0.82 \begin {gather*} \frac {1}{15} x^{15} b^{4} + \frac {4}{13} x^{13} b^{3} a + \frac {6}{11} x^{11} b^{2} a^{2} + \frac {4}{9} x^{9} b a^{3} + \frac {1}{7} x^{7} a^{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^6*(b^2*x^4+2*a*b*x^2+a^2)^2,x, algorithm="fricas")

[Out]

1/15*x^15*b^4 + 4/13*x^13*b^3*a + 6/11*x^11*b^2*a^2 + 4/9*x^9*b*a^3 + 1/7*x^7*a^4

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giac [A]  time = 0.15, size = 46, normalized size = 0.82 \begin {gather*} \frac {1}{15} \, b^{4} x^{15} + \frac {4}{13} \, a b^{3} x^{13} + \frac {6}{11} \, a^{2} b^{2} x^{11} + \frac {4}{9} \, a^{3} b x^{9} + \frac {1}{7} \, a^{4} x^{7} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^6*(b^2*x^4+2*a*b*x^2+a^2)^2,x, algorithm="giac")

[Out]

1/15*b^4*x^15 + 4/13*a*b^3*x^13 + 6/11*a^2*b^2*x^11 + 4/9*a^3*b*x^9 + 1/7*a^4*x^7

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maple [A]  time = 0.00, size = 47, normalized size = 0.84 \begin {gather*} \frac {1}{15} b^{4} x^{15}+\frac {4}{13} a \,b^{3} x^{13}+\frac {6}{11} a^{2} b^{2} x^{11}+\frac {4}{9} a^{3} b \,x^{9}+\frac {1}{7} a^{4} x^{7} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^6*(b^2*x^4+2*a*b*x^2+a^2)^2,x)

[Out]

1/7*a^4*x^7+4/9*a^3*b*x^9+6/11*a^2*b^2*x^11+4/13*a*b^3*x^13+1/15*b^4*x^15

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maxima [A]  time = 1.33, size = 46, normalized size = 0.82 \begin {gather*} \frac {1}{15} \, b^{4} x^{15} + \frac {4}{13} \, a b^{3} x^{13} + \frac {6}{11} \, a^{2} b^{2} x^{11} + \frac {4}{9} \, a^{3} b x^{9} + \frac {1}{7} \, a^{4} x^{7} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^6*(b^2*x^4+2*a*b*x^2+a^2)^2,x, algorithm="maxima")

[Out]

1/15*b^4*x^15 + 4/13*a*b^3*x^13 + 6/11*a^2*b^2*x^11 + 4/9*a^3*b*x^9 + 1/7*a^4*x^7

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mupad [B]  time = 0.02, size = 46, normalized size = 0.82 \begin {gather*} \frac {a^4\,x^7}{7}+\frac {4\,a^3\,b\,x^9}{9}+\frac {6\,a^2\,b^2\,x^{11}}{11}+\frac {4\,a\,b^3\,x^{13}}{13}+\frac {b^4\,x^{15}}{15} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^6*(a^2 + b^2*x^4 + 2*a*b*x^2)^2,x)

[Out]

(a^4*x^7)/7 + (b^4*x^15)/15 + (4*a^3*b*x^9)/9 + (4*a*b^3*x^13)/13 + (6*a^2*b^2*x^11)/11

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sympy [A]  time = 0.08, size = 53, normalized size = 0.95 \begin {gather*} \frac {a^{4} x^{7}}{7} + \frac {4 a^{3} b x^{9}}{9} + \frac {6 a^{2} b^{2} x^{11}}{11} + \frac {4 a b^{3} x^{13}}{13} + \frac {b^{4} x^{15}}{15} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**6*(b**2*x**4+2*a*b*x**2+a**2)**2,x)

[Out]

a**4*x**7/7 + 4*a**3*b*x**9/9 + 6*a**2*b**2*x**11/11 + 4*a*b**3*x**13/13 + b**4*x**15/15

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